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2 years ago

In the figure, s // t, find the m<1

Mathematics

1 answer:

Neporo4naja [7]2 years ago

6 0

Answer:

m<1=115°(Alternative interior Angles)

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The average of 6 ages men is 35 years and the average of four of them is 32. Find the ages of the remaining two men if one is 3

prisoha [69]

Answer:

the first one must be 39.5 and the other 42.5

Step-by-step explanation:

multiply 35 by 6 and subtract 32 x 4 you are left with 82. Divide that by 2 and make the difference 3.

6 0

2 years ago

The length of a pool table is 71 feet and the width is 36 feet. Find the area of the surface of the pool table by multiplying th

Zarrin [17]

Answer:

2556 feet squared

Step-by-step explanation:

Area is calculated by multiplying length times width. 71x36=2556

5 0

2 years ago

ryan reads 2/5 chapters in 3/4 hours. What is the unite rate in chapters per hour write your answer in simplest form

saw5 [17]

Answer:

0.53 chapters per hour or 8/15 chapters per hour

Step-by-step explanation:

2/5 chapters = 0.4 chapters

3/4 hours = 0.75 hours

0.4/0.75 = 0.53 chapters per hour

7 0

2 years ago

A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo

katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the box $V=x^2z$

Volume of the box $=12 ft^3\\$

$Therefore, x^2z=12\\z=\frac{12}{x^2}$

The material for the base costs $\$0.17/ft^2$ , the material for the sides costs $\$0.10/ft^2$ , and the material for the top costs $\$0.13/ft^2$ .

Area of the base $=x^2$

Cost of the Base $=\$0.17x^2$

Area of the sides $=4xz$

Cost of the sides= $=\$0.10(4xz)$

Area of the Top $=x^2$

Cost of the Base $=\$0.13x^2$

Total Cost, $C(x,z) =0.17x^2+0.13x^2+0.10(4xz)$

Substituting $z=\frac{12}{x^2}$

$C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}$

To minimize C(x), we solve for the derivative and obtain its critical point

$C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2$

Recall: $z=\frac{12}{x^2}=\frac{12}{2^2}=3\\$

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0

2 years ago

I have finished the table but stuck in the question after...

lisov135 [29]

Answer:

7/48

Step-by-step explanation:

there are 48 in total

there are 7 white females

7/48

4 0

3 years ago