All categories

3 years ago

Find the range of all the multiples of 3 between 10 and 20

Mathematics

2 answers:

devlian [24]3 years ago

7 0

Answer:

multiples of 3 between 10 and 20 is 12,15 and 18

Len [333]3 years ago

3 0

List the multiples of 3:

3, 6, 9, 12, 15, 18,21

The ones between 10 and 20 are:

12, 15, 18

The range is the difference between the highest and lowest numbers.

Range = 18 - 12 = 6

You might be interested in

On a parallelogram, the vector from one vertex to another vertex is (9,-2). What is the length of the side?

sertanlavr [38]

Answer: Second Option is correct.

Step-by-step explanation:

Since we have given that

In a parallelogram, the vector from one vertex to another vertex is (9,-2)

So, the co-ordinate of first vertex will be (9,0).

And the coordinate of second vertex will be (0,-2).

As we know the formula for "Distance between two coordinates":

So, The length of the side is given by

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\Distance=\sqrt{(9-0)^2+(0-(-2))^2}\\\\Distance=\sqrt{9^2+2^2}\\\\Distance=\sqrt{81+4}\\\\Distance=\sqrt{85}$

Hence, Second Option is correct.

6 0

3 years ago

Read 2 more answers

Fay has a lemonade stand.

AnnyKZ [126]

Answer:

her total profit is 3

Step-by-step explanation:

1.50 x 30 = 45

to find total profit - 45-42= 3

5 0

3 years ago

Read 2 more answers

100.5 divided by 1.5

wariber [46]

The answer to 100.5 divided by 1.5 is 67

5 0

3 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago

Which is bigger 5/8 or 7/12

gladu [14]

5/8=0.625

7/12=0.583......

5/8 is bigger as ive put both into a decimal as it is easier to tell

4 0

3 years ago

Read 2 more answers