Simplify the following:
(y^6 y^8)/((2 x^2)/(x^4))
Combine powers. (y^6 y^8)/((x^2×2)/x^4) = (y^(8 + 6) x^(4 - 2))/2:
(y^(8 + 6) x^(4 - 2))/2
8 + 6 = 14:
(y^14 x^(4 - 2))/2
4 - 2 = 2:
Answer: (y^14 x^2)/2
For the mode to be 6, there has to be at least two 6s.
For the median to be 6, with two 6s, there must be at least one number above 6.
For the mean to be 6, the sum is 30, so the three remaining numbers must total 18.
Step-by-step explanation:
3x+18+2x-5= -2x+-2+10
combining like terms
3x+2x+2x=5-2+10-18
7x=-5
x=-5/7
Answer:
m = 28
Step-by-step explanation:
70 × 2 = 5m
140 = 5m
28 = m
Answer:
5 pigs
Step-by-step explanation:
A farmhouse shelters 16 animals, some are pigs, and some are ducks. Altogether there are 42 legs. How many pigs are there?
Let us represent:
Number of pigs = x
Number of ducks = y
Our system of equations is given as:
A farmhouse shelters 16 animals, some are pigs, and some are ducks.
x + y = 16...... Equation 1
x = 16 - y
Altogether there are 42 legs.
Ducks have 2 legs(feet) , pigs have 4 legs,
4x + 2y = 42..... Equation 2
We substitute
16 - y for x in Equation 2
Hence:
4(16 - y) + 2y = 42
64 - 4y + 2y = 42
Collect like terms
- 4y + 2y = 42 - 64
-2y =- 22
y = -22/-2
y = 11 ducks
Solving for x.
x = 16 - y
x = 16 - 11
x = 5 pigs
Therefore, we have 5 pigs