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2 years ago

Write the slope intercept form. Anyone of them would be so helpful

Mathematics

1 answer:

natita [175]2 years ago

3 0

y=1/3x+1
y=7/2x+3
y=x
y=-x+1
y+1=2(x-1)
y+2=-7/2(x-5)
y+2=5/3(x+3)
y-5=-1/6(x+5)

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Please help and please give explanation

Yuki888 [10]

Answer:

cylinder surface area = 201.06in²

surface area of cone = 56.56in.²

Step-by-step explanation:

cylinder surface area formula = 2πrh + 2πr²

refer the pic

cone surface area formula = πr ( r + √h² + r² )

refer the sec pic

surface area of the solid

= ( 201.06 + 56.56 ) in.²

= 257.62in.²

= 258in.²

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2 years ago

How many hours did Diana work of she was paid $45.50

JulijaS [17]

I think it would be C because the equation is y=7x. y=7x is also equal to x=1/7y. If y=45.50, then you would have to divide y by 7, which would equal 6.5.

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2 years ago

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Neporo4naja [7]

101 miles.
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3 years ago

How do I solve this problem

Anton [14]

What does the rest of the problem say?

5 0

2 years ago

A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the

Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the width W as such

$W = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that $\sigma^{2} = 9$ , then $\sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3$ . So

$W = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.96*\frac{3}{\sqrt{n}}$

$\sqrt{n} = 1.96*3$

$(\sqrt{n})^2 = (1.96*3)^{2}$

$n = 34.57$

Rounding up

A sample size of 35 is needed.

3 0

2 years ago