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Vanyuwa [196]
3 years ago
8

What is the value of 7x^2 + 3x + 4 when x=2?

Mathematics
2 answers:
Nonamiya [84]3 years ago
8 0

Answer:

38

Step-by-step explanation:

substitute the value of the variable into an equation, then simplify

DerKrebs [107]3 years ago
3 0

Answer:

38

Step-by-step explanation:

To find the value of 7x^2 + 3x + 4 when x=2. We have to plug in x. So plugging x in, we have

7(2)^2 +3(2) +4

and this becomes

7(4) + 6 +4

or

8(4)+6

which is 38

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I need help please help
vesna_86 [32]

Answer:

C. (x-2)^2=7

Step-by-step explanation:

What you have to do first is to get rid of the 3 in the x^2 so you will divide 3 by the whole thing to get x^2-4x=3.

You will then divide -4 by 2 and then square the answer to get 4.

You will then add the 4 into the end of the equation and to the 3 to get x^2-4x+4=7.

You will then make into a perfect square (x-2)^2=7 and that is your answer.

5 0
3 years ago
What equals 12.5 in multiplication
kramer
2 x 6.25 
is equal to 12.5 in multiplication
7 0
3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
Evaluate the expression 7^2/ x^2 - 2 for x = 3
vovikov84 [41]

Answer:

7

Step-by-step explanation:

7²/x²-2 when x=3

49/3²-2

49/9-2

49/7

answer=7

4 0
3 years ago
Please need help I will be MARKING as BRIANILIST. thank you so much. ​​
ryzh [129]

Answer:

C

Step-by-step explanation:

I am guessing that's it.

8 0
3 years ago
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