Answer:
B'(-7 , -2)
Step-by-step explanation:
First we must understand the coordinate-axis, when we want to move a point to the left or right we do it on the x-axis. to move up or down is on the y axis.
now if we move to the left we go to the negative and to the right the positive
as we are going to move to the left we have to subtract the value that he gave us (4) only to the part of x
B(-3 , -2)
-3 - 4 = -7
B'( -7 , -2)
This is a pathagorean triple is this triangle is a right triangle
Circle<span> is the locus of points equidistant from a given point, the center of the </span>circle<span>. The common distance from the center of the </span>circle<span> to its points is called radius. Thus a </span>circle<span> is completely </span>defined<span> by its center (O) and radius (R): C(O, R) = O(R) = {x: dist(O, x) = R}.
Easier explanation: </span><span>A </span>circle<span> is a plane figure contained by one line such that all the straight lines falling upon it from one point among those lying within the figure are equal to one another.</span>
Please put a thanks so i know your question was answered. It helps since im new here and really boosts my morale :D
if x =4 and y =-3
F =
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Add '-1' to each side of the equation.
1 + -1 + 3d = 10 + -1
Combine like terms: 1 + -1 = 0
0 + 3d = 10 + -1
3d = 10 + -1
Combine like terms: 10 + -1 = 9
3d = 9
Divide each side by '3'.
d = 3
Simplifying
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