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Gnoma [55]
3 years ago
7

2x+8<5x-4 solve the inequality

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

x>4

Step-by-step explanation:

2x+8<5x-4

subtract 8 from both sides

2x<5x-12

subtract 5x from both sides

-3x<-12

divide both sides by -3 to get x by itself

(REMEMBER THAT WHEN YOU DIVIDE BY NEGATIVES IN INEQUALITIES, THAT YOU HAVE TO FLIP THE INEQUALITY SIGN)

x>4

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Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them is 300 m
MrRissso [65]

Answer:

The faster train goes 60mph

Step-by-step explanation:

s= speed

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Then you are given:

200/s+s+20=2

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3 years ago
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


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