Explanation:
how much the project will cost
public class 4by4Square
{
public static void main(){
System.out.println("xxxx \nx x\nx x\nxxxx");
}
}
<h2><u>~CaptnCoderYankee</u></h2>
It depends on a language you code. I think this could be either C++ or Java. I know answer for both of them.
For C++: <span>address.find("Avenue")
For Java: </span><span>address.indexOf("Avenue")</span>
Data visualization
Data visualization is a good starting point for data mining. There are several approaches to data mining that supports smart decisions. Data visualization places data in a visual context. It extracts the data in a clear and understandable way without any form of reading or writing. Results are displayed in the form of pie charts, graphs, and any other statistical representation. Such multidimensional views of data aid in developing a preliminary understanding of the trends that are hidden in the data set.
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
