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sergeinik [125]
3 years ago
6

Grass can grow up to six inches in 7 days depending on the temperature, humidity, and time of year. At this rate, how tall will

the grass grow in 28 days?
Mathematics
2 answers:
Charra [1.4K]3 years ago
8 0

Answer:

24 inches

Step-by-step explanation:

if the temperature humidity and time of year is based on an average

Drupady [299]3 years ago
8 0
24 inches. 6 inches of growth in 7 days. 28 days / 7 =4. 4x6=24. Unless it mentions something about the temperature, humidity and time of year being anything other than average this is answer.
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Murrr4er [49]
1 solution. it can't be 2, and if you solve it, there is a solution, x stays in the equation, so there's 1 solution
5 0
3 years ago
A study showed that low intensity shock therapy reduces pain levels in patients with lupus.  during each session electrodes ar
Irina18 [472]

Answer:

it would be answer a

Step-by-step explanation:

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4 0
3 years ago
find the smaller of 2 consecutive integers,x, if the sum of the smaller and 6 times the larger is -29
AnnyKZ [126]

Answer:-  The smaller integer is -5.


Explanation:-

Let the first consecutive integer be x and the second consecutive integer be x+1.

According to the given question:-

x+6(x+1)= -29

⇒x+6x+6= -29   [distributive law]

⇒x+6x= -29-6    [subtract 6 on the both sides]

⇒7x= -35      [combining like terms ]

⇒x= -5          [dividing 7 on both sides]

Thus the smaller integer =x= -5

larger integer =x+1= -5+1= -4

3 0
3 years ago
The scatter plot below shows the distances some employees of a company commute to work and the annual
salantis [7]

Answer:

It is a

Step-by-step explanation: I looked it up

6 0
3 years ago
Simplify the expression below and write it as a single logarithm:
OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

<u>Solution:</u>

Given, expression is 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

Rearranging the terms we get,

\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)

\text { since a } \times \log b=\log \left(b^{a}\right)

\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)

\text { We know that } \log a \times \log b=\log a b

\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.

\text { We know that } \log a-\log b=\log \frac{a}{b}

\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

Hence, the simplified form \rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

4 0
3 years ago
Read 2 more answers
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