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3 years ago

Can someone help me out?

Mathematics

1 answer:

jonny [76]3 years ago

8 0

Answer:

Step-by-step explanation:

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Tell whether the ratios form a proportion. 14:8 and 28:10

Dima020 [189]

Answer:

Step-by-step explanation:

14:8 = 14/8 = 7/4

28:10 = 28/10 = 14/5

Since the fractions are not equal, it is not a proportion.

Answer: no

5 0

2 years ago

Classify the system of equations 3x+y-1=0 1/3x+y-6=0 A. intersecting B. parallel C.coincident

barxatty [35]

Answer: Intercepting.

Step-by-step explanation:

1. To solve this problem and classify the system of equations shown above, you can graph it has you can see in the graph attached.

2. As you can see the lines intersect each other, this means that the system of equation has one solution and the lines are intersecting.

3. Therefore, the answer is the option A: Intersecting.

7 0

3 years ago

Read 2 more answers

C=1/21.22.23+1/22.23.24+................+1/200.201.202 . = là dấu nhân

Aneli [31]

It looks like you have to find the value of the sum,

$C = \displaystyle \frac1{21\times22\times23} + \frac1{22\times23\times24} + \cdots + \frac1{200\times201\times202}$

so that the n-th term in the sum is

$\dfrac1{(21+(n-1))\times(21+n)\times(21+(n+1))} = \dfrac1{(n+20)(n+21)(n+22)}$

for 1 ≤ n ≤ 180.

We can then write the sum as

$\displaystyle C = \sum_{n=1}^{180} \frac1{(n+20)(n+21)(n+22)}$

Break up the summand into partial fractions:

$\dfrac1{(n+20)(n+21)(n+22)} = \dfrac a{n+20} + \dfrac b{n+21} + \dfrac c{n+22}$

Combine the fractions into one with a common denominator and set the numerators equal to one another:

$1 = a(n+21)(n+22) + b(n+20)(n+22) + c(n+20)(n+21)$

Expand the right side and collect terms with the same power of n :

$1 = a(n^2+43n+462)+b(n^2+42n+440) + c(n^2+41n + 420) \\\\ 1 = (a+b+c)n^2 + (43a+42b+41c)n + 462a+440b+420c$

Then

a + b + c = 0

43a + 42b + 41c = 0

462a + 440b + 420c = 1

==> a = 1/2, b = -1, c = 1/2

Now our sum is

$\displaystyle C = \sum_{n=1}^{180} \left(\frac1{2(n+20)}-\frac1{n+21}+\frac1{2(n+22)}\right)$

which is a telescoping sum. If we write out the first and last few terms, we have

C = 1/(2×21) - 1/22 + 1/(2×23)

… … + 1/(2×22) - 1/23 + 1/(2×24)

… … + 1/(2×23) - 1/24 + 1/(2×25)

… … + 1/(2×24) - 1/25 + 1/(2×26)

… … + … - … + …

… … + 1/(2×198) - 1/199 + 1/(2×200)

… … + 1/(2×199) - 1/200 + 1/(2×201)

… … + 1/(2×200) - 1/201 + 1/(2×202)

Notice the diagonal pattern of underlined and bolded terms that add up to zero (e.g. 1/(2×23) - 1/23 + 1/(2×23) = 1/23 - 1/23 = 0). So, like a telescope, the sum collapses down to a simple sum of just six terms,

C = 1/(2×21) - 1/22 + 1/(2×22) + 1/(2×201) - 1/201 + 1/(2×202)

which we simplify further to

C = 1/42 - 1/44 - 1/402 + 1/404

C = 1,115/1,042,118 ≈ 0.00106994

4 0

3 years ago

Given that √5 ≈ 2.2360679775 and ???? ≈ 3.1415926535, find the sum √5 + ???? to an accuracy of 10−8 without using a calculator.

muminat

Answer:

√5 + π = 537766063.1 × $10^{-8}$

Step-by-step explanation:

given data

√5 ≈ 2.2360679775

π ≈ 3.1415926535

to find out

√5 + π

solution

√5 + π = 2.2360679775 + 3.1415926535

√5 + π = 5.3776606310

√5 + π = 5.3776606310 × $\frac{10^{-8}}{10^{-8}}$

√5 + π = 537766063.1 × $10^{-8}$

3 0

3 years ago

What is the area of this trapezoid?

navik [9.2K]

Answer:

A = 32

Step-by-step explanation:

A = ½ (a + b) h

A = ½ (3 + 10) 4

A = (3+5)4

A = (8)4

A = 32

8 0

3 years ago