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STatiana [176]
3 years ago
5

What type of reaction will have each of this mixtures?

Chemistry
1 answer:
kari74 [83]3 years ago
4 0

Answer:

no reaction bro ok have a good day

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Fossil fuels contribute to about 85% of the total energy produced in the world. What is a direct environmental
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How many moles are equal to 1.4 x 10^24 atoms of aluminum
Svetlanka [38]

Answer: 2.3 moles

Explanation:

Recall that based on Avogadro's law, 1 mole of any substance has 6.02 x 10^23 atoms

So if 1 mole of Aluminum = 6.02 x 10^23 atoms

Then, Z moles = 1.4 x 10^24 atoms

To get the value of Z, we cross multiply:

1 mole x 1.4 x 10^24 atoms = Z x (6.02 x 10^23 atoms)

1.4 x 10^24 atoms = Z x (6.02 x 10^23)

Hence, Z = (1.4 x 10^24 atoms) ➗ (6.02 x 10^23 atoms)

Z =2.3 moles

Thus, there are 2.3 moles in 1.4 x 10^24 atoms of aluminum.

4 0
4 years ago
You are asked to bring the pH of 0.500L of 0.550 M NH4Cl to 7.00. Which of the following solutions would you use: 12.0 M HCl or
ch4aika [34]
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. What elements are present in the following chemical formula?<br>KNO3​
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A chemist wishing to do an experiment requiring 47Ca2+(half-life = 4.536 days) needs 5.00 g of the nuclide. What mass of 47CaCO
Artyom0805 [142]

Answer: The answer is 6.78 grams.

Explanation: The equation used for solving this type of problems  is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount of radioactive substance, N is the remaining amount and n is the number of half lives.

Number of half lives is calculated on dividing the given time by the half life.

n = time/half life

Time is given as 48.0 hours and the half life is given as 4.536 days. let's make the units same and for this let's convert the half life from days to hours.

4.536days(\frac{24hours}{1day})

= 108.864 hours

So, n=\frac{48.0}{108.864}  = 0.441

Since 5.00 g is the required amount when the radioactive substance is delivered to the scientist, it would be the final amount that is N. We need to calculate the initial amount. Let's plug in the values in the equation:

\frac{5.00}{N_0}=(\frac{1}{2})^0^.^4^4^1

\frac{5.00g}{N_0}=0.737

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So, 6.78 g of the radioactive substance needs to be ordered.

4 0
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