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velikii [3]
3 years ago
15

A chemist repeats the gold foil experiment but she uses foil made of aluminum(atomic number 79). How would you expect her result

s to compare with the experiment that used gold foil?
Chemistry
1 answer:
Tanya [424]3 years ago
3 0
Omg I wish I knew this one sorry



Hope you can figure it out
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A hot air balloon, when fully inflated, contains 2,800,000 Liter of air. If each mole of air occupies 22.4 L of at a temperature
emmainna [20.7K]

Answer:

1.44 atm

Explanation:

Step 1:

We'll begin by calculating the number of mole in 2,800,000 Liter of air.

I mole of air occupy 22.4L.

Therefore, Xmol of air will occupy 2800000L i.e

Xmol of air = 2800000/22.4

Xmol of air = 125000 moles

Step 2:

Determination of the pressure when the balloon is fully inflated .

This can be obtained as follow:

Number of mole (n) of air = 125000 moles

Volume (V) = 2800000 L

Temperature (T) = 120°C = 120°C + 273 = 393K

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =.?

PV = nRT

Divide both side V

P= nRT/V

P= (125000x0.082x393) / 2800000

P = 1.44 atm

Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm

3 0
3 years ago
Which type of succession will occur in this
nexus9112 [7]

Answer:

secondary, because there are some remains of the previous community (C)

Explanation:

6 0
3 years ago
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How would you prepare 1 liter of .030 m copper 2 sulfate pentahydrate?
Ierofanga [76]
Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.
V(CuSO₄·5H₂O) = 1 L.
c(CuSO₄·5H₂O) = 0,30 mol/L.
n(CuSO₄·5H₂O)  = V(CuSO₄·5H₂O) · c(CuSO₄·5H₂O) .
n(CuSO₄·5H₂O) = 1 L · 0,3 mol/L.
n(CuSO₄·5H₂O) = 0,3 mol.
m(CuSO₄·5H₂O) = n(CuSO₄·5H₂O) · M(CuSO₄·5H₂O).
m(CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.
m(CuSO₄·5H₂O) = 74,9 g.
5 0
3 years ago
When turgor pressure is high enough in a cell, the cell walls become _____
iren2701 [21]

Answer:

the answer is "Firm".

Explanation:

6 0
3 years ago
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Consider the following element combinations. Classify the bonds formed between each pair as ionic, polar covalent, or nonpolar c
Sati [7]

An ionic bond is formed by the transfer of electrons from one atom to the other. It is usually formed between a metal + non-metal.

A covalent bond is formed by sharing of electrons between two atoms. It is formed between two nonmetals. A polar covalent bond is formed between 2 non-metals which differ in their electronegativities. In contrast, in a non-polar covalent interaction the two atoms could either be the same or have very close electronegativities.

1) P and I : Both non-metals with different electronegativities= Polar Covalent

2) Fe and O: Metal + non-metal = Ionic

3) S and Cl: Both non-metals with different electronegativities= Polar Covalent

4) S and S: Both non-metals and the same atoms = Non-polar Covalent

5) Br and Br: Both non-metals and the same atoms = Non-polar Covalent

6) O and Cl: Both non-metals with different electronegativities= Polar Covalent

7) Be and Cl: Metal + non-metal = Ionic

8) Al and N: Metal + non-metal = Ionic

5 0
3 years ago
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