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tatyana61 [14]
3 years ago
13

You are asked to bring the pH of 0.500L of 0.550 M NH4Cl to 7.00. Which of the following solutions would you use: 12.0 M HCl or

12.0 M NH3? How many drops (1 drop 0.05 mL ) of this solution would you use?
The answer to part one is 12.0 M NH3 but how do you answer the second part?

Thank you
Chemistry
1 answer:
ch4aika [34]3 years ago
6 0
<span>1 drop is approximately 0.05mL. Since 0.500L of 0.550M NH4Cl contains 0.275mol of substance (calculated by using c=n/V formula), equal amount of substance of NH3 is needed to neutralize this solution (since pH of 7 is neutral solution). Thus, we need 0.0275L of NH3, i.e. around 550 drops.</span>
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\frac{?grams}{1 mole} =\frac{0.896grams}{0.0104moles}                                      <----- Proportion

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?grams = 86.2                                               <----- Divide both sides by 0.0104

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