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2 years ago

In Problems 1-8, determine the level of measurement of each variable.

Mathematics

1 answer:

lbvjy [14]2 years ago

3 0

The level of measurement of each given variable are:

1. Ordinal

2. Nominal

3. Ratio

4. Interval

5. Ordinal

6. Nominal

7. Ratio

8. Interval

Level of measurement is used in assigning measurement to variables depending on their attributes.

There are basically four (4) levels of measurement (see image in the attachment):

1. Nominal: Here, values are assigned to variables just for naming and identification sake. It is also used for categorization.

Examples of variables that fall under the measurement are: Favorite movie, Eye Color.

2. Ordinal: This level of measurement show difference between variables and the direction of the difference. In order words, it shows magnitude or rank among variables.

Examples of such variables that fall under this are: highest degree conferred, birth order among siblings in a family.

3. Interval Scale: this third level of measurement shows magnitude, a known equal difference between variables can be ascertain. However, this type of measurement has no true zero point.

Examples of the variables that fall here include: Monthly temperatures, year of birth of college students

4. Ratio Scale: This scale of measurement has a "true zero". It also has every property of the interval scale.

Examples are: ages of children, volume of water used.

Therefore, the level of measurement of each given variable are:

1. Ordinal

2. Nominal

3. Ratio

4. Interval

5. Ordinal

6. Nominal

7. Ratio

8. Interval

Learn more about level of measurement here:

brainly.com/question/20816026

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At a factory, 450 bottles of ketchup are produced each hour.Write an equation that can be used to show the relationship between

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Answer:

450 × n

Step-by-step explanation:

Let B be the number of bottles of ketchup

Let h be the time taken in hours

For 1 hour, 450 bottles of ketchup are produced

For n hours, 450 × n bottles of ketchup will be produced

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3 years ago

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have: