(7-1/8) - (1-7/8) = 57/8 -15/8 = 21/4
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)
taking another point (-1,5)
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)
b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1
Step-by-step explanation:
I couldn't put this full page.
Thankfully I found the answer
Answer:
2 ( one significant figure)
Step-by-step explanation:
798/8 x 41 in order to express it in 1 significant figure
we will multiply the denominator and then divide both the numerator and denominator.
so,
798/328
798/328
2.453
now to one significant figure it will be 2
