Question

How many moles of potassium hydroxide (KOH) are needed to completely neutralize 1.56 mol phosphoric acid (H3PO4)?

Answer 1

.56 mol H3PO4 x (3 mol KOH/1 mol H3PO4)=4.68 mol KOH.

Answer 2

Answer : The number of moles of potassium hydroxide (KOH) are needed to completely neutralize are 4.68 moles.

Explanation :

The balanced chemical reaction will be:

$3KOH+H_3PO_4\rightarrow K_3PO_4+3H_2O$

From the balanced chemical reaction we conclude that,

As, 1 mole of $H_3PO_4$ neutralizes 3 moles of KOH

So, 1.56 mole of $H_3PO_4$ neutralizes $1.56\times 3=4.68$ moles of KOH

Thus, the number of moles of potassium hydroxide (KOH) are needed to completely neutralize are 4.68 moles.