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2 years ago

Which substance is a base? HCOOH RbOH H2CO3 NaNO3

Chemistry

2 answers:

harkovskaia [24]2 years ago

7 0

Answer:

RbOH

Explanation:

Alex Ar [27]2 years ago

6 0

Answer:

RbOH

Explanation:

For this question, we have to remember what is the definition of a base. A base is a compound that has the ability to produce hydroxyl ions $OH^-$ , so:

$AOH~->~A^+~+~OH^-$

With this in mind we can write the reaction for each substance:

$HCOOH~->~HCOO^-~+~H^+$

$RbOH~->~Rb^+~+~OH^-$

$H_2CO_3~->~CO_3^-^2~+~2H^+$

$NaNO_3~->~Na^+~+~NO_3^-$

The only compound that fits with the definition is $RbOH$ , so this is our base.

I hope it helps!

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9. For each reaction listed, identify the proton donor (or acid) and the proton acceptor(or base).

Talja [164]

Answer:

Explanation:

conjugate acid, based on Brønsted–Lowry acid–base theory, is a chemical compound that is formed by the reception of a proton by a base

a. CH₃COOH + H₂O ⇌ H₃0⁺ + CH₃C00-

Acid <> CH₃COOH

Base <> H₂O

Conjugate acid <> H₃0 +

Conjugate base <>CH₃C00-

b. HCO₃ + H₂O ⇌ H₂CO₃⁻ + OH⁻

Acid <> H₂O

Base <> HCO₃

Conjugate acid <> H₂CO₃⁻

Conjugate base <>OH⁻

C. HNO₃ + SO₄²⁻ ⇌ HSO₄⁻ + NO₃⁻

Acid <>HNO₃

Base <>SO₄²⁻

Conjugate acid <>HSO₄⁻

Conjugate base <>NO₃⁻

A Bronsted acid is reffered to as a proton donor while a Bronsted base is a proton acceptor

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3 years ago

Interesting facts about coal

babunello [35]

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3 years ago

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The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con

bonufazy [111]

Answer: The concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

Explanation:

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

We are given:

$t_{1/2}=3.82days$

Putting values in above equation, we get:

$k=\frac{0.693}{3.82}=0.181days^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.181days^{-1}$

t = time taken for decay process = 3.00 days

$[A_o]$ = initial amount of the reactant = $1.45\times 10^{-6}mol/L$

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}$

$[A]=3.83\times 10^{-30}mol/L$

Hence, the concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

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3 years ago

The elements chlorine and iodine have similar chemical properties because they _____. Group of answer choices have the same numb

worty [1.4K]

Answer:

Have the same number of electrons in their outer energy levels

Explanation:

Elements in the same group have similar chemical properties because they have the same number of valence electron(s) in their outermost shell.

Chlorine and Iodine have similar chemical properties because they have the same number of valence electron in their outermost shell. This can be seen from their electronic configuration as shown below:

Cl (17) => 1s² 2s²2p⁶ 3s²3p⁵

I (53) => [Kr] 4d¹⁰ 5s²5p⁵

From the above illustration:

Outer shell of Cl (3s²3p⁵) = 2 + 5 = 7 electrons

Outer shell of I (5s²5p⁵) = 2 + 5 = 7 electrons

Since they have the same number of valence electrons, therefore, they will have similar chemical properties.

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2 years ago

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kap26 [50]

Answer:

31.1°C

Explanation:

Given parameters:

Temperature = 88°F

The formula of the to convert is:

T°F = T°C - 32 / 1.8 = $\frac{TC - 32}{1.8}$

Now input the parameters and solve;

T°F = $\frac{ 88 -32}{1.8}$

T°F = 31.1°C

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2 years ago

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