Its D for the second energy level, but the first energy level is 2.
        
                    
             
        
        
        
Answer:
b. 0.22 L
Explanation:
Step 1: Write the balanced equation
4 HNO₃(l) ⇒ 4 NO₂(g) + 2 H₂O(l) + O₂(g)
Step 2: Calculate the moles corresponding to 2.5 g of HNO₃
The molar mass of HNO₃ is 63.01 g/mol.
2.5 g × 1 mol/63.01 g = 0.040 mol
Step 3: Calculate the moles of O₂ produced from 0.040 moles of HNO₃
The molar ratio of HNO₃ to O₂ is 4:1. The moles of O₂ produced are 1/4 × 0.040 mol = 0.010 mol.
Step 4: Calculate the volume corresponding to 0.010 moles of O₂
Assuming the reaction takes place at standard temperature and pressure, the volume of 1 mole of O₂ is 22.4 L.
0.010 mol × 22.4L/1 mol = 0.22 L
 
        
             
        
        
        
Answer:
The answer to your question is: density = 0.993 g/ml
Explanation:
Data
mass beaker empty = 29.3 g
volume of liquid = 15 ml
mass beaker + liquid = 44.2 g
Formula 
              density = mass / volume
Process
mass of liquid = 44.2 - 29.3
                        = 14.9 g
              density = 14.9 / 15
                           = 0.993 g/ml
 
        
             
        
        
        
Answer:
The value is  
Explanation:
 From the question we are told that 
     The equation is  
      The  temperature is  ![T = 25^oC =  298 K   [room  \ temperature ]](https://tex.z-dn.net/?f=%20T%20%3D%2025%5EoC%20%3D%20%20298%20K%20%20%20%5Broom%20%20%5C%20temperature%20%5D)
      The  emf at standard condition is  
Generally at the cathode 
       
   At the anode 
       
Generally for an  electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as  
        
Here  n  is  the no of electron  with value n = 6 
        F  is  the Faraday's constant with value 96487 J/V
   =>    
 
   =>   
This Gibbs free energy can also be represented mathematically as 
        
Here  R  is the cell constant with value 8.314J/K 
            K is the equilibrium constant 
From above 
=>  
Generally  antilog =  2.718
=>
=>   