What is the pOH of a 4.8 x 10^-10 M H+ solution?

2 answers:

4 0

Answer:
pOH = 4.68

Explanation:
1- getting the pH of the solution:
pH = -log[H+]
We have:
[H+] = 4.8 * 10⁻¹⁰ M
Therefore:
pH = -log[4.8 * 10⁻¹⁰]
pH = 9.3187 which is approximately 9.32

2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated:
pH = 9.32
Therefore:
pOH = 14 - 9.32 = 4.68

Hope this helps :)

spin [16.1K]3 years ago

3 0

The pOH of a 4.8 x 10^-10 M H+ solution is pOH = 4.68
Get the pH through this formula:pH = -log[H+]So,[H+] = 4.8 * 10⁻¹⁰ MpH = -log[4.8 * 10⁻¹⁰]pH = 9.32

So, apply this formula:pH + pOH = 14if pH = 9.32, thenpOH = 14 - 9.32 = 4.68

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