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serg [7]
3 years ago
11

The sphere's radius is one-third the radius of the hemisphere. How does the volume of this hemisphere compare with the volume of

the sphere?
Mathematics
2 answers:
liraira [26]3 years ago
6 0
Volume of the sphere = 3/4 pi r^3 

The spheres radius is one third of the hemisphere's so radius of hemisphere = 3r 
Volume of the hemisphere = 1/2 * 4/3 pi (3r)^3
                                         =   2/3 * 27 pi r^3
                                         =  18 pi r^3
So vol hemisphere / vol sphere =  18 pi r^3 / 4/3 pi r^3 = 18 * 3/4 =  13.5

Hemisphere is 13.5 times the volume of the sphere.
Elena-2011 [213]3 years ago
3 0

Answer:

Its greater than the volume of the sphere.

Step-by-step explanation:


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A construction crew built 1/3 miles of road in 1/6 days
Ganezh [65]

Answer:

2 miles per day

Step-by-step explanation:

The length of the road built is 1/3 miles, so let's call L = 1/3

The time spent to build this length is 1/6 days, so let's call D = 1/6

To find the unit rate in miles per day, that is, the speed that this length of the road was built, we just need to divide L by D (speed is distance over time). Let's call the speed S:

S = D/T

S = (1/3) / (1/6)

S = (1/3) * 6

S = 2 miles per day

5 0
3 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
Solve for x<br> Enter the solutions from least to greatest.<br> -4x^2– 7 = -11
Pavlova-9 [17]

Answer:

x = 1, x = -1

Step-by-step explanation:

-4x² = -4

x² = 1

x = \sqrt{1}

x = ±1

3 0
3 years ago
Which fraction is equal to 0.5 7
Andrei [34K]
14.25/25 I hope this helps
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3 years ago
What does <br><br>"mixed number in its lowest form." mean?
Viktor [21]

Answer:

ok so it basically means reducing a mixed number to its simplest form.

4 0
3 years ago
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