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1 year ago

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A consumer charges a $50 purchase on a credit card. The card has a daily interest rate of 0.038%. If the consumer pays off the b

alance at the end of 30 days, how much in interest will be paid
for the purchase? Round your answer to two decimal places.

1 answer:

Mariana [72]1 year ago

4 0

Answer:

SIMPLE ONE-TIME INTEREST

I

=

P

0

r

A

=

P

0

+

I

=

P

0

+

P

0

r

=

P

0

(

1

+

r

)

I is the interest

A is the end amount: principal plus interest

P0 is the principal (starting amount)

r is the interest rate (in decimal form. Example: 5% = 0.05

Step-by-step explanation:

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P=2L +2W;P=32,W=7<br><br> 25<br> 16<br> 12.5<br> 9

Marianna [84]

Answer:

L = 9

Step-by-step explanation:

Assuming you are trying to find L

P = 2L + 2W

P = 32

32 = 2L + 2W

W = 7

32 = 2L + (2 × 7)

32 = 2L + 14

2L = 32 - 14

2L = 18

L = 9

5 0

2 years ago

If r + 14 = -9, what justifies r = -23

kramer

Answer:

you subtract 14 from -9 and that justifies it

Step-by-step explanation:

Hope this helps

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2 years ago

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If you know a car travels 30 km in 20 minutes you can find its

Daniel [21]

Answer:

You can find its average speed.

Step-by-step explanation:

To find average speed you can divide distance by time which has been given.

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3 years ago

An equation is shown below:

Tasya [4]

5(2x-8)+15=-15 -15 in both sides 5(2x-8)=-30 /5 2x-8=-6 +8 2x=2 /2 x=1 I hope it helps

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2 years ago

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strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0

2 years ago