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Lady bird [3.3K]
2 years ago
7

What theorem can be used to prove these triangles are congruent? ASA SAA neither

Mathematics
2 answers:
Leviafan [203]2 years ago
6 0
ASA- 2 pairs of congruent angles and I pair of congruent sides but is NOT located between the pairs of angles
mixas84 [53]2 years ago
5 0
ASA is the theorem i think
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Answer:

It 20.54 round to the nearest tenth which is 20.5

Step-by-step explanation:

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In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4

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fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

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x+1\neq0

x\neq-1

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Help please and simply it
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-6, because -6^3 is -215
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