5. What is the solution to the linear-quadratic system of equations?
1 answer:
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Use the way that kids use i.e trial and error method .
Solution:-
The set given by
Lets understand
- See the first term any natural value will make it natural .
Come to 2nd one.
- n should be a multiple of 8 to make it whole.
Come to third one
- n should be a number which makes the sum a perfect square by which we get a natural no.We have to solve it w.r.t to 2nd one
Lets think
Nearest squares to 225 are 196 and 289
We can't take 196 as we have to take a positive one other wise it will come in terms of i.
Take 289
Its divisible by 8 .
Rewrite the set
Hence n=64