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morpeh [17]
3 years ago
6

( BRAINLIEST) Few drops of thymolphthalein indicator will change acid to...

Chemistry
2 answers:
storchak [24]3 years ago
7 0

Answer:

Explanation:

Stays colourless

posledela3 years ago
3 0

A few drops of thymolphthalein indicator will not change an acid's colour

hope it helps

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Where is almost all the mass of an atom​
VashaNatasha [74]
The nucleus!! This is made up of protons and neutrons that each weigh about 1 amu.

Electrons are not found in the nucleus and weigh almost nothing so chemistry in school doesn’t bother with them :)
8 0
3 years ago
Please help with this, i don't really get how to do this
LuckyWell [14K]
#4 and #5:
To find pH given concentration of H+ or H30+
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8 0
3 years ago
What element is primarily used in appliances to make electronic chips
sineoko [7]

Answer:

Option A

Explanation:

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6 0
4 years ago
Read 2 more answers
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

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72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
Electrolysis is used in the electroplating of metals. The same amount of current is passed through separate aqueous solutions of
Aleonysh [2.5K]

Answer:

CuSO4 cell will have the greatest amount of deposit among all three. The deposit will occur at the cathode

Explanation:

The valence of the elements in this case is as follows -

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Sn - 4e-

Cr - 3e-

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3 0
3 years ago
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