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Black_prince [1.1K]
2 years ago
14

Determine the formula weight of caffeine, C₈H₁₀N₄O₂. Provide an answer to two decimal places.

Chemistry
2 answers:
arlik [135]2 years ago
5 0

Let's find

\\ \tt\hookrightarrow C_8H_10N_4O_2

  • We need accurate mass

\\ \tt\hookrightarrow 8(12.011)+10(1.007)+4(14.006)+2(16.0)

\\ \tt\hookrightarrow 96.088+10.07+56.024+32.0

\\ \tt\hookrightarrow 196.182g/mol

\\ \tt\hookrightarrow 196.18g/mol\:or 196.18u

Rashid [163]2 years ago
5 0

Answer:

IPO you have to be a Goodgood of you

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How many moles of oxygen molecules are present in 112ml of co2 at NTP?​
dexar [7]

In each mole of carbon dioxide there will be one mole of O₂.

Let us calculate the moles of carbon dioxide gas present first

The conditions are NTP it means , Temperature = 293 K and P = 1 atm

We will use ideal gas equation

PV= nRT

Where

P = Pressure of gas = 1 atm

V= 112mL=0.112L

R= gas constant =0.0821 L atm /mol K

n = moles = ?

Putting values

moles=\frac{PV}{RT}=\frac{1X0.112}{0.0821X293}

moles = 0.00466

Thus moles of carbon dioxide will be 0.00466

The moles of O₂ = 0.00466

7 0
3 years ago
5 example of similarities between compression and tension stress?​
tiny-mole [99]

Answer:

Mark me as Brainliest please

Explanation:

Compression vs Tension

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6 0
3 years ago
During Georgia’s sever drought what recreational facility was under construction
RUDIKE [14]

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4 0
3 years ago
Read 2 more answers
The empirical formula for trichloroisocyanuric acid, the active ingredient in many household bleaches is OCNCI. The molar mass o
TEA [102]

Answer:

These two are equivalent and valid:

       C_3Cl_3N_3O_3

       Cl_3(CN)_3O_3

Explanation:

The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.

<u />

<u>1. Determine the mass of the empirical formula:</u>

OCNCl:

Atomic masses:

  • O: 15.999g/mol
  • C: 12.011g/mol
  • N: 14.007g/mol
  • Cl: 35.453g/mol

Total mass:

  • 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol

<u />

<u>2. Divide the molar mass by the mass of the empirical formula:</u>

  • 232.41g/mol / 77.470g/mol = 3

<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>

       O_3C_3N__3Cl_3

Or:

       C_3Cl_3N_3O_3

You might also write CN as a group:

          Cl_3(CN)_3O_3

8 0
3 years ago
Is one unlit match an example of a physical or chemical change, or a physical or chemical property?​
Korolek [52]

I believe it’s physical property because there is no chemical reaction to an unlit match‍♀️

8 0
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