Definitely B. Chemicals are used to help clean difficulties items/objects
Answer:
-0.276 Degrees C
Explanation:
kf of water is 1.86
Freezing point depression= m x kf x i
i= ions present ( K+ Cl-) 1=2
1.86x2X.743= .276
Since its freezinf point depression the freezing point will lower
so
0-.276= -.276
Answer:
47.5 g of water can be formed
Explanation:
This is the reaction:
CH₄ + 2O₂ → CO₂ + 2H₂O
Methane combustion.
In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.
As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.
1.320 mol .2 = 2.64 moles
Now, we can convert the moles to mass (mol . molar mass)
2.64 mol . 18g/mol = 47.5 g
Answer:
Grams of the reactant would be required is 8.26 g
Explanation:
Decomposition of NI3 is :
2 NI3 (s) --------------------> N2 (g)............... +..................... 3 I2 (g)
2 mol..................................1 mol.........................................3 mol
2 x 394.7 g/mol..............28 g/mol....................................3 x 253.8 g/mol
789.4 g...............................28 g...........................................761.4 g
From chemical equation it is cleared that
761.4 g of iodine is obtained from = 789.4 g of NI3
Therefore,
7.97 g of iodine is obtained from = 789.4 g x 7.97 g / 761.4 of NI3
= 6291.518 / 761.4 of NI3
= 8.26 g of NI3
Hence
Grams of the reactant would be required = 8.26 g