Taking into account the definition of density, the mass of a substance with a volume of 150 cm³ and a density of 1.5 
is 225 grams.
<h3>What is density</h3>
Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
<h3>Mass of the substance in this case</h3>
In this case, you know that:
- Density= 1.5
- Volume= 150 cm³
Replacing in the definition of density:
Solving:
mass= 1.5 ×150 cm³
<u><em>mass= 225 g</em></u>
In summary, the mass of a substance with a volume of 150 cm³ and a density of 1.5 is 225 grams.
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The atomic number is the same as the number of protons, so the answer is 25.
Answer:
The heat of formation of SO2 is -296.1 kJ
Explanation:
<u>Step 1:</u> Data given
2S (s)+3O2 (g)→2SO3 (g) ΔH = -790.4 kJ
2SO2 (g)+O2 (g)→2SO3 (g) ΔH = -198.2 kJ
<u>Step 2</u>: Calculate the heat of formation of SO2
2 S(s) + 3 O2(g) --> 2 SO3(g) ΔH = -790.4 kJ
S(s) + 3/2 O2(g) → SO3(g) ΔH = -395.2 kJ
2SO2 (g)+O2 (g)→2SO3 (g) ΔH = -198.2 kJ
SO3(g) → SO2(g) + 1/2 O2(g) ΔH = 99.1 kJ
----------------------------------------------------------------
S(s) + 3/2 O2(g) → SO3(g) ΔH = -395.2 kJ
SO3(g) → SO2(g) + 1/2 O2(g) ΔH = 99.1 kJ
-------------------------------------------------------------------
S (s)+O2 (g)→SO2 (g)
ΔHrxn = (-790.4 /2) kJ + (198.2/2) kJ
ΔHrxn = -395.2 kJ + 99.1 kJ = 296.1 kJ
The heat of formation of SO2 is -296.1 kJ
Answer:
17
Explanation:
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