<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
Answer:
1/2
Step-by-step explanation:
It is a independent problem. Flipping a head the first time will not affect the other results therefore it is still one half.
a) because the denominators are the same add the numerators:
1 1/5 + 3 2/5 = 4 3/5
b) rewrite the fractions to have a common denominator:
1/2 = 3/6
1/3 = 2/6
Now subtract:
4 3/6 - 1 2/6 = 3 1/6
