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2 years ago

9

Find the area of a circle with radius, r = 5.99m. Give your answer rounded to 2 DP.

1 answer:

GalinKa [24]2 years ago

3 0

Answer: 112.72

Step-by-step explanation: We know that the formula for area of a circle is pi*r^2. Now we plug in the values. pi*5.99^2. Next we get rid of the exponent. 5.99*5.99 = 35.8801. Now we have pi*35.8801. Now if you are gonna use actual pi for this your answer would be 112.72065857. Round it to 2 decimal points and you have 112.72 . If you do 35.8801*3.14=112.663514 -> Round this and you have 112.66. So any of them would actually work but I would stick with 112.72.

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Find the Error. Judith states that -|14| = 14 because the absolute value can never be negative. Find her mistake and correct it.

AURORKA [14]

Answer:

-14

Step-by-step explanation:

The negative sign is not inside of the absolute value sign so it would be -14

5 0

2 years ago

Can you help with this one?

deff fn [24]

Answer:

27

90

70

35

Step-by-step:

should be 27 too

90 degree

70 degree

would be around 35

27+70 = x

97 = x

4 0

3 years ago

Write eachfraction units simplest form.<br><br> 18/4= ____. 24/32=_______

disa [49]

Answer:18/4= 9/2

24/32= 3/4

Step-by-step explanation:

for 18/4 divide both numbers by 2

= 9/2

for 24/32 divide both numbers by 8

=3/4

5 0

3 years ago

Read 2 more answers

antoniya [11.8K]

Answer: 82°

Step-by-step explanation:

<CDE = far arc - near arc / 2

i.e

<CDE = arcCBE - arcCE / 2

arcCE = 98°

arcCBE = 360° - 98° = 262°

<CDE = 262° - 98° / 2

<CDE = 164 / 2

<CDE = 82°

Therefore the measure of < CDE is 82°

8 0

3 years ago

Read 2 more answers

The perimeter of the flag is 2080 ft what is the flags width and length of the length is 420 ft greater than the width

hram777 [196]

Answer:

The length of the flag is 730 ft and the width is 310 ft

Step-by-step explanation:

<u><em>The correct question is</em></u>

The perimeter of the flag is 2080 ft what is the flags width and length <u>if</u> the length is 420 ft greater than the width

Let

L ----> the length of the flag

W ---> the width of the flag

we know that

The perimeter of the flag (rectangle) is equal to

$P=2(L+W)$

we have

$P=2,080\ ft$

so

$2,080=2(L+W)$

$1,040=L+W$ ----> equation A

$L=W+420$ ---> equation B

Solve the system by substitution

substitute equation B in equation A

$1,040=(W+420)+W$

solve for W

$1,040=2W+420$

$2W=1,040-420$

$2W=620$

$W=310\ ft$

<em>Find the value of L</em>

$L=W+420$ ----> $L=310+420=730\ ft$

therefore

The length of the flag is 730 ft and the width is 310 ft

5 0

3 years ago