Find the perimeter of triangle abc with vertices a(-1,2) b(3,6) c(3,-2)
the perimeter is 27
∵AB＝CB
∴∠BAC＝∠BCA
∵AB bisect ∠MAT
∴∠MAB＝∠TAB
Hope my answer helped u :)
Step-by-step explanation:
-5h/50 = -0.1
-1h/10 = -0.1
Multiply both sides by (10/-1)
(10/-1)(-1h/10)= (10/-1)(-0.1)
h= 1
In this parallelogram, by definition angles 2 and 3 are alternate interior and have the same measure, and angle 1 and 37degrees have the same measure. So angle 1 = 37. the other angle inside there that's not marked is supplementary with 63, so it measures 180 - 63 = 117. So angle 3, then, by the Triangle angle-sum theorem measures 180 - 37 - 117 = 26. As stated earlier, angles 2 and 3 are the same, so 2 is also 26. And I think we got them all! 1=37, 2 and 3 = 26.
Yes but at the same time you have to look for the range and domain
