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Aliun [14]
2 years ago
12

Carmen is mailing packages. Each small package costs her $2.60 to send. Each large package costs her $3.40. How much will it cos

t her to send 7 small packages and 4 large packages?
(need help asap please)
Mathematics
1 answer:
Fantom [35]2 years ago
6 0

Answer:

By themselves $18.20, $13.60, and together $31.80

Step-by-step explanation:

$2.60 multiplied by 7 equals $18.20

$3.40 multiplied by 4 equals $13.60

Together this equals $31.80

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HELPPPP PLZZ ND THANK YOU SOO MUCH
swat32

Answer:

50, 40, 30, 250, 350

Step-by-step explanation:

1/2 = 0.5, 0.5 x 100 = <u>50</u> (0.5 -> 5 -> 50)

2/5 = 0.4 (10 / 5 [the denominator] = 2, 0.2 x 2 [the numerator] = 0.4), 0.4 x 100 = <u>40</u> (0.4 -> 4 -> 40)

3/10 = (10 / 10 [the denominator] = 1, 0.1 x 3 [the numerator] = 0.3), 0.3 x 100 = <u>30</u> (0.3 -> 3 -> 30)

5/2 = 2.5 (2 1/2), 2.5 x 100 = <u>250</u> (2.5 -> 25 -> 250)

7/2 = 3.5 (3 1/2), 3.5 x 100 = <u>350</u> (3.5 -> 35 -> 350)

Note: I'm not sure if I understand the question completely, but I changed the fraction into a decimal and multiplied it by 100. Not sure what it means by "<u><em>Divide</em></u><em> fraction</em>".

3 0
2 years ago
An empty cubical carton is side 7cm. Can you fill 1000 cubes of side 1cm in it ?
Shalnov [3]
An empty cubical carton of side 7cm has the volume:
7 x 7 x 7 = 343cm³

A cube of side 1cm has the volume:
1 x 1 x 1 = 1cm³

From this, we can see that a 1000 cubes of side 1cm has the volume:
1000 x 1cm³ = 1000cm³

But we know that the cubical carton of side 7cm only has a volume of 343cm³.

Since 1000cm³ > 343cm³,
you cant fill 1000 cubes of side 1cm in such a carton.

TL;DR
No

Hope this helps
8 0
2 years ago
Please solve this i really need this
d1i1m1o1n [39]

Answer:

a = 8 (to nearest whole number)

Step-by-step explanation:

Given:

m<B = 36°

m<C = 104°

c = 12

Required:

a

SOLUTION:

✔️First find m<A:

m<A = 180 - (104 + 36)

m<A = 40°

✔️Find a using Sine Rule:

Thus:

\frac{a}{sin(A)} = \frac{c}{sin(C)}

Plug in the values

\frac{a}{sin(40)} = \frac{12}{sin(104)}

Multiply both sides by sin(40)

\frac{a}{sin(40)} * sin(40) = \frac{12}{sin(104)} * sin(40)

a = \frac{12*sin(40)}{sin(104)}

a = 8 (nearest whole number)

4 0
2 years ago
In which quadrant does the point P(–1, 5) lie?
vesna_86 [32]
Quadrant number II
The quadrant II has the negative x axis and the positive y axis
8 0
3 years ago
There are 5 questions on a multiple choice exam, each with five possible answers. If a student guesses on all five questions, wh
Mrac [35]

Answer:

20.5\%

Step-by-step explanation:

Let's write out a case for two specific questions being correct and the rest being incorrect:

\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5},

The \frac{1}{5} represents the chances of getting the question correct, as there are 5 answers and 1 correct answer choice.

The \frac{4}{5} represents the chances of getting the question incorrect, as there are 5 answers and 4 incorrect answer choices.

The equation above does show the student getting two answers correct and three answers incorrect, but it only shows one possible case of doing so.

We can choose any two of the five questions to be the ones the student gets correct. Therefore, we need to multiply this equation by the number ways we can choose 2 from 5 (order doesn't matter): \binom{5}{2}=10.

Therefore, the probability the student gets two questions correct is:

\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \binom{5}{2}=\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot 10=0.2048\approx \boxed{20.5\%}

6 0
3 years ago
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