Question

Q). If | 1 , 1, 3 | A = | 5, 2, 6 |, then find A³ | -2, -1, -3 |​

Answer 1

Answer:

A³ = [ 1, 1, 27, 125, 8, 216, -8, -1, -27].

Step-by-step explanation:

All the numbers in the bracket should be cubed.

I hope you understood ♥️♥️♥️

Answer 2

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given matrix is

$\rm :\longmapsto\: \begin{gathered}\sf A=\left[\begin{array}{ccc}1&1&3\\5&2&6\\ - 2&-1& - 3\end{array}\right]\end{gathered}$

Consider,

$\red{\rm :\longmapsto\: {A}^{2}}$

$\rm \: = \: A \times A$

$\\ \rm \: = \: \begin{gathered}\sf \left[\begin{array}{ccc}1&1&3\\5&2&6\\ - 2&-1& - 3\end{array}\right]\end{gathered}\begin{gathered}\sf \left[\begin{array}{ccc}1&1&3\\5&2&6\\ - 2&-1& - 3\end{array}\right]\end{gathered}$

$\rm \: = \: \begin{gathered}\sf \left[\begin{array}{ccc}1 + 5 - 6&1 + 2 - 3&3 + 6 - 9\\5 + 10 - 12&5 + 4 - 6&15 + 12 - 18\\ - 2 - 5 + 6&-2 - 2 + 3& - 6 - 6 + 9\end{array}\right]\end{gathered}$

$\rm \: = \: \begin{gathered}\sf \left[\begin{array}{ccc}0&0&0\\3&3&9\\ - 1&-1& - 3\end{array}\right]\end{gathered}$

$\\ \bf\implies \: {A}^{2} = \begin{gathered}\sf \left[\begin{array}{ccc}0&0&0\\3&3&9\\ - 1&-1& - 3\end{array}\right]\end{gathered}$

Now, Consider

$\red{\rm :\longmapsto\: {A}^{3}}$

$\rm \: = \: {A}^{2} \times A$

$\\ \rm \: = \: \begin{gathered}\sf \left[\begin{array}{ccc}0&0&0\\3&3&9\\ - 1&-1& - 3\end{array}\right]\end{gathered} \times \begin{gathered}\sf \left[\begin{array}{ccc}1&1&3\\5&2&6\\ - 2&-1& - 3\end{array}\right]\end{gathered}$

$\\ \rm \: = \: \begin{gathered}\sf \left[\begin{array}{ccc}0&0&0\\3 + 15 - 18&3 + 6 - 9&9 + 18 - 27\\ - 1 - 5 + 6&-1 - 2 + 3& - 3 - 6 + 9\end{array}\right]\end{gathered}$

$\\ \rm \: = \: \begin{gathered}\sf \left[\begin{array}{ccc}0&0&0\\0&0&0\\ 0&0&0\end{array}\right]\end{gathered}$

$\\ \bf\implies \: {A}^{3} = \: \begin{gathered}\sf \left[\begin{array}{ccc}0&0&0\\0&0&0\\ 0&0&0\end{array}\right]\end{gathered}$

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Learn More :-

Matrix multiplication is defined when number of columns of pre multiplier is equal to the number of rows of post multiplier.

Matrix multiplication may or may not be Commutative.

Matrix multiplication is Associative. i.e (AB)C = A(BC)

Matrix multiplication is Distributive. i.e. A ( B + C ) = AB + AC