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vivado [14]
4 years ago
9

Simplify the following 3/4(1/2× - 12)+4/5

Mathematics
2 answers:
Vesna [10]4 years ago
8 0

<u>Answer:</u>

The value of \frac{3}{4}\left(\frac{1}{2} \times-12\right)+\frac{4}{5} is -\frac{37}{10} or (-3.7)

<u>Solution: </u>

\frac{3}{4}\left(\frac{1}{2} \times-12\right)+\frac{4}{5}

Simplifying the equation we get,

\left(\frac{3}{4}\right) \times\left(\frac{1}{2} \times(-12)\right)+\frac{4}{5}

\left(\frac{3}{4}\right) \times\left(\frac{-12}{2}\right)+\left(\frac{4}{5}\right)

Dividing -12 and 2,

[(\frac{3}{4})\times(-6)]+ (\frac{4}{5})

\frac{3 \times(-6)}{4}+\left(\frac{4}{5}\right)

\frac{-18}{4}+\left(\frac{4}{5}\right)

Bringing \frac{-18}{4} to its simplest form of fraction,

\left(-\frac{9}{2}\right)+\left(\frac{4}{5}\right)

\left(\frac{4}{5}\right)-\left(\frac{9}{2}\right)

Factors of 5 = 5\times1

Factors of 2 = 2\times1

Therefore, Least Common multiple of 5 and 2 is 10.

\frac{8-45}{10}

-\frac{37}{10} = (-3.7)

irga5000 [103]4 years ago
3 0

Step-by-step explanation:

3/4 ×1/-24 +5/5

3×1/4×-24+4/5

3×1/4×-24+4/5

3/-96+4/5

-3/96+4/5

-1/32+4/5

ans:123/160

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The height of a right triangle is √6 units and the base is √9 units. Find the area of the triangle
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Step-by-step explanation:

h = √6 units

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The diameter of circles A,C and E are 32 cm, 24cm and 14 cm respectively
Karolina [17]

Answer:

AG = 4

AH = 21

EC = 12

CH = 5

HE = 7

Step-by-step explanation:

<u><em>The complete question is</em></u>

The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.

Which of the following statements are true? Select all that apply.

•AG = 4

•GC = 10

•AH = 21

•EC = 12

•EH = 5

•CH = 5

•HE = 7

The picture of the question in the attached figure

<u><em>Verify each statement</em></u>

1) AG = 4

we know that

AG=AC-GC

AC=32\2=16\ cm ----> radius of circle A

GC=24/2=12\ cm ----> radius of circle C

substitute

AG=16-12=4\ cm

therefore

The statement is true

2) GC = 10

we know that

GC=24/2=12\ cm ----> radius of circle C

therefore

The statement is false

3) AH = 21

we know that

AH=AC+CH

we have

AC=16\ cm ----> radius of circle A

CH=CE-HE

CE=12\ cm ----> radius of circle C

HE=14/2=7\ cm ----> radius of circle E

so

CH=12-7=5\ cm

AH=16+5=21\ cm

therefore

The statement is true

4) EC = 12

we know that

EC=24/2=12\ cm ----> radius of circle C

therefore

The statement is true

5) EH = 5

we know that

EH=14/2=7\ cm ----> radius of circle E

therefore

The statement is false

6) CH = 5

we know that

CH=CE-HE

CE=12\ cm ----> radius of circle C

HE=14/2=7\ cm ----> radius of circle E

so

CH=12-7=5\ cm

therefore

The statement is true

7) HE = 7

we know that

HE=14/2=7\ cm ----> radius of circle E

therefore

The statement is true

3 0
3 years ago
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