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hammer [34]
3 years ago
15

Help me simplify this, please!!

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0
- \sqrt[3]{2 x^{4} y^{2}  } *3 \sqrt[3]{20 x^{5}y } =-3  \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} =  \\ \\ =-3 \sqrt[3]{40 x^{9}  y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9}  y^{3}  } = \\  \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} }  \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}
Answer: B.
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Substitute y into into the original equation:

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y = (11•³√4)/3

So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).

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