We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.
</span>we have that
<span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3
radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2
A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>
Answer:
8.) 3
9.) x+5
10.) 50x/2x-5
11. 3n4-n3(cubed)/n3+n2-n-1
Step-by-step explanation:
Yo is this a trick question? Hahaa
Answer:120 square cm
Step-by-step explanation:
40 x 3
The third choice - 65.3%.
He made 66 successful attempts out of 101 total free throws. To find the experimental probability, it will be 66 divided by 101.
66 successful / 101 total attempts = 0.6534
Rounded off to the nearest tenth of a percent - 65.3%
The experimental probability that you make a free throw is 65.3%.
