Answer:
yes because every time x changes y changes the same amount
Step-by-step explanation:
Where is the problem at? give me the url
(1)
f(x) + g(x) = 3x + 2 + 2x + 5 = 5x + 7
f(x) - g(x) = 3x + 2 - 2x - 5 = x - 3
(2)
f(x) + g(x) = 4x - 1 + 3x - 4 = 7x - 5
f(x) - g(x) = 4x - 1 - 3x + 4 = x + 3
(3)
f(x) + g(x) = - 5x + 3 + 2x - 4 = - 3x - 1
f(x) - g(x) = - 5x + 3 - 2x + 4 = - 7x + 7
(4)
f(x) + g(x) = 3x - 4 - 2x + 3 = x - 1
f(x) - g(x) = 3x - 4 + 2x - 3 = 5x - 7
(5)
f(x) × g(x) = - 2(- x + 7 ) = 2x - 14
(6)
f(x) × g(x) = - 5(2x - 7) = - 10x + 35
In order for it to be divisible by 5 AND be an even number, it must also be divisible by 2. So you are looking for two-digit numbers greater than 34 and divisible by 10:
C = {40, 50, 60, 70, 80, 90}
5280 rounds up to 6000 because the number 8 is after 5, so your round up which makes 5280, 6000.