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2 years ago

7

If the cost of a graphing calculator is now three-fourths of what the calculator cost 5 years ago and the cost of the graphing c

alculator is now $78. Find the cost of the calculator 5 years ago.

1 answer:

Andru [333]2 years ago

3 0

Answer:

58 1/2

Step-by-step explanation:

multiply by 3/4

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Divide:<br> 5/11 •2/5 <br> HURRY PLEASE

Kamila [148]

Answer:

0.1818

Step-by-step explanation:

0.4545 x 0.4

3 0

3 years ago

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Robert drew a parallelogram with 2 55 degree angles. What are the measures of the 2 other angles? Both of the angles have to be

Licemer1 [7]

Angles in a parallelogram have to equal 360.

Let x represent the measurement of the unknown angle.

2(55) + 2x = 360
110 + 2x = 360
2x = 250
x = 125

125 degrees

5 0

3 years ago

How is this solved using trig identities (sum/difference)?

GenaCL600 [577]

FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

$cos \beta = -\frac{1}{2} \sqrt{3}$

$tan \beta= \frac{1}{3} \sqrt{3}$

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
$sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )$
$sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )$
$sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})$

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
$cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )$
$cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )$
$cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )$

Find tan (α - β)
$tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha tan \beta }$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}$

Simplify the denominator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5\sqrt{3}}{24})}$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the numerator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$
$tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the fraction
$tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})$
$tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}$

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2 years ago

HELP ILL GIVE BRAINLIEST PLS QUICK

saveliy_v [14]

Answer:

Y =2X +2

y = 2(13) + 3

y = 29 after 13 months

Step-by-step explanation:

x1 y1 x2 y2

0 2 2 6

(Y2-Y1) (6)-(2)= 4 ΔY 4

(X2-X1) (2)-(0)= 2 ΔX 2

slope= 2

B= 2

Y =2X +2

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2 years ago

So, the area <br> Find the area of the figure of

ch4aika [34]

Answer:

The area of the figure is 117m²

Step-by-step explanation:

In this problem, you have two shapes. One shape is a rectangle. The other shape is a triangle.

Area of a rectangle = b*h = 9*7 = 63

Area of a triangle = $\frac{1}{2}$ (b*h) =

Since there are two triangles, you will multiply the area of the one triangle in the figure by 2.

27*2 = 54

Now, you add up the areas!

54 + 63 = 117

So, the area of the figure is 117m²

7 0

3 years ago

Read 2 more answers