Let m and j be the current ages of Matthew and Jenny, respectively.
Now, Matthew is 3 times as old as Jenny, so the variables are in the following relation:
In 7 years, both of them will be 7 years older, i.e. their ages will be m+7 and j+7, and Matthew will be twice as old:
Now, remembering that m=3j, we can rewrite the second equation as
So, Jenny is 7 and Matthew is 21 (he's 3 times older).
In fact, in 7 years, they will be 14 and 28, and Matthew will be twice as old.
Answer:
Minimum = 10
Q1 (quartile 1) = 14.5
Medium = 16
Q3 (quartile 3) = 17
Maximum = 18
Step-by-step explanation:
You just arrange the numbers in from smallest to greatest (even if some of them repeat). Then, look for the maximum and minimum. Get the median by having the same numbers left from both sides until reaching the median. The same holds for the quartiles (if you have for example two numbers for the quartile, as in this case 14 and 15, add the up and divide them by 2, in this case 14.5.
Tell me if I'm correct please
Answer: 32/20 or 8/5
Step-by-step explanation: Turn 7/5 into 28/20. Do 28/20 plus 4/20. That equals 32/20 or 8/5.
Answer:
Yes
Step-by-step explanation:
So I'll assume that x3 is 3x -->
so 3x • 3x • 3x =? to 3x • 3 • 3?
You can first simplify this to 3^3x =? to 3x • 9 -->
27x =? to 3x • 9 => so there are many solutions but if per say x = 5 then yes it would be equal.
Check with another number per instance 8
27(8) = 216 => 24(9) = 126
Yes they are equal
Hope this helps!
