All categories

3 years ago

How to solve for j -10=║j-7║

Mathematics

1 answer:

Aleksandr [31]3 years ago

6 0

Answer:

No solutions.

Step-by-step explanation:

-10 = 7

No solutions

You might be interested in

Factor:

nekit [7.7K]

Answer:

a) $(7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)$

b) $(7\cdot a\cdot b^{8}+1)\cdot (7\cdot a\cdot b^{8}-1)$

c) $a = 0.7\cdot t^{9}$

d) There are two possible answers only considering real coefficients:

(i) $16\cdot x^{2}-81 = (4\cdot x +9)\cdot (4\cdot x - 9)$

(ii) $14\cdot x^{2}-81 =(\sqrt{14}\cdot x+9)\cdot (\sqrt{14}\cdot x - 9)$

e) $(a^{3}+4)\cdot (a^{3}-4)$

Step-by-step explanation:

Now we proceed to solve each algebraic equation:

a) Factor $49\cdot m^{12}-16$

This binomial is of the form $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . In this case, we can rewrite and factor the equation below:

$49\cdot m ^{12}-16$

$(7\cdot m^{6})^ 2-4^{2}$

$(7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)$

b) Factor $49\cdot a^{2}\cdot b^{16}-1$

This binomial is of the form $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . In this case, we can rewrite and factor the equation below:

$49\cdot a^{2}\cdot b^{16}-1$

$(7\cdot a\cdot b^{8})^{2}-1^{2}$

$(7\cdot a\cdot b^{8}+1)\cdot (7\cdot a\cdot b^{8}-1)$

c) Nicole is factoring $0.49\cdot t^{18}-25$ by using the rule $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . What will she use for the value of $a$ ?

From this rule we find that $a^{2} = 0.49\cdot t^{18}$ , that is:

$a^{2} = 0.49\cdot t^{18}$

$a^{2} = \frac{49}{100}\cdot t^{18}$

$a = \frac{7}{10}\cdot t^{9}$

$a = 0.7\cdot t^{9}$

d) Which binomial is a difference of squares?

A binomial is a difference of square if and only if $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . There are two possible answers only considering real coefficients:

(i) $16\cdot x^{2}-81 = (4\cdot x +9)\cdot (4\cdot x - 9)$

(ii) $14\cdot x^{2}-81 =(\sqrt{14}\cdot x+9)\cdot (\sqrt{14}\cdot x - 9)$

e) Factor $a^{6}-16$

This binomial is of the form $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . In this case, we can rewrite and factor the equation below:

$a^{6}-16$

$(a^{3})^{2}-4^{2}$

$(a^{3}+4)\cdot (a^{3}-4)$

6 0

3 years ago

Question 10

vazorg [7]

Answer:

$83,320

Step-by-step explanation:

The formula to apply here is;

$A=P(1+\frac{r}{n} )^{nt}$

where;

A=Amount at the end

P=the amount to invest/principal

r=rate of interest as a decimal

n=number of compoundings in a year

t=time in years

Given that;

A=$400,000

P=?

r=8%=0.08

n=2

t=20

Substitute values in equation

$A=P(1+\frac{r}{n} )^{nt} \\\\\\400,000=P(1+\frac{0.08}{2} )^{2*20} \\\\\\400,000=P(1+0.04)^{40} \\\\\\\\400,000=P(1.04)^{40} \\\\\\400,000=P(4.80102062794)\\\\\\\\\frac{400,000}{4.80102062794} =\frac{4.80102062794P}{4.80102062794} \\\\\\83315.617=P\\\\$

P=$83,320 (to the nearest dollar)

8 0

3 years ago

What is 591/9120 plz answer corretly

larisa [96]

Answer:

simplified will be 197/3040. as a decimal it is 0.06480263157

Step-by-step explanation:

pls give brainilist and have an AMAZING DAY!!!

7 0

4 years ago

PLEASE HELP WILL GIVE POINTS PLEEEEASE!!!!!!!!!!!!!!

mixer [17]

Answer:

b=-2

Step-by-step explanation:

3√-8 = -2

-2^3 = -8

8 0

4 years ago

8X - 35 = 7(1 + 2X)

lawyer [7]

Answer: x=-7

Step-by-step explanation:

8X - 35 = 7(1 + 2X)

8x - 35 = 7 + 14x

-6x - 35 = 7

-6x = 42

X = -7

3 0

3 years ago