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barxatty [35]
3 years ago
8

Find the distance between the two points shown. A) 5 B) 7 C) 21 D) 27

Mathematics
2 answers:
andrezito [222]3 years ago
7 0

Answer: 7 points

Step-by-step explanation: You can count from one point to the other point

kotegsom [21]3 years ago
4 0

Answer:

It is B, 7 points.

Step-by-step explanation:

You can start from the point (8,2) and then you go up 7 points to reach the point (8,9) which is 7 points.

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How long will a boy take to run round a square field of side 35 meters, if he runs at the rate of 9 km/hr?.
NNADVOKAT [17]

Answer: It is 56 seconds.

5 0
1 year ago
Successfulness of the Competition policy in South Africa- support and graphs​
jenyasd209 [6]

Answer:

Answer to the following question is a follows;

Step-by-step explanation:

The following are a few examples of how South Africa's competitiveness policy has been successful:

⇒ Consumers or buyers were given a variety of product options as well as competitive prices.

⇒ In 1984, practises like horizontal cooperation and resale price maintenance and control were ruled illegal.

6 0
2 years ago
What is the standard form of y –7 = – 23 (x + 1)
ValentinkaMS [17]

Answer:

23x+y=-16

Step-by-step explanation:

7 0
3 years ago
Priya makes bracelets for her online store. Her monthly business expenses are $520. She sells an average of 80 bracelets per
ch4aika [34]

Answer:

B

Step-by-step explanation:

Profit = total revenue - total cost

total revenue = 80 x b

total cost = 520

the profit has to be at least $1240

80 x 22 = 1760

1760 - 520 = 1240

b is correct

5 0
2 years ago
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
2 years ago
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