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Leni [432]
3 years ago
15

What is uniforlmly acelerated motion and uniform motion​

Physics
1 answer:
steposvetlana [31]3 years ago
8 0

Uniformly Accelerated motion : When a body moves along a straight line and its velocity increases by equal amounts in equal interval of time then the motion is called uniformly accelerated motion. E.g.:- Motion of a freely falling body.

Uniform Motion : When a body covers equal distances in a straight line, equal intervals of time are called uniform motion. Example: a car moving at 20km/h in a straight line. When a body covers unequal distance in equal intervals of time in a straight line is called non-uniform Example : spinning wheel.

<h3>Difference About Uniformly Accelerated motion And Uniform Motion</h3>

In Uniform Velocity Motion a body will be moving with a constant /unchanging velocity moving in a particular direction and thus acceleration will be zero whereas in Uniform accelerated motion a body will move at constant acceleration and its velocity will keep changing with time at a constant/ steady rate.

<h2>IF YOU THINK MY ANSWER IS WRONG, CHANGE IT THANK YOU. </h2>
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Answer:

1.75g

Explanation:

Given parameters:

Density  = 3.5g/cm³

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Density is the mass per unit volume of a substance

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So;

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Two clocks are taken from the Earth to the Moon. The first clock uses a pendulum mechanism, while the second uses a spring-loade
yulyashka [42]

Answer:

Part 1. Pendulum clock is slower.

Part 2. Spring-loaded clock remains the same.

Explanation:

The period of a simple pendulum is given by

T=2\pi\sqrt{\dfrac{l}{g}}

where l = length of pendulum and g = acceleration due to gravity.

It is seen that the period is inversely proportional to the square root of the gravitational acceleration. So if gravity increases, period decreases and vice versa.

g on the moon is about one-fifth that of the Earth. Hence, the pendulum will have a larger period, about twice (\sqrt{5} = 2.24). A larger period means it takes longer to finish an oscillation, so the pendulum clock is slower.

The period of a loaded spring is given by

T=2\pi\sqrt{\dfrac{k}{m}}

where k = the spring constant and m = mass of load on the spring.

It is seen that this relation does not depend on gravity nor does it have any parameter that depends on gravity: k is a constant of the spring that does not change while mass is independent of location.

Hence, the spring-loaded clock will remain the same.

As a note, one might assume that gravity affects the loaded spring because the load is 'pushed' down by gravity. In fact, only the equilibrium position is affected by gravity; it only determines where the oscillation starts from, not how long it takes.

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