Answer:
The answer is below
Explanation:
1.5 - kΩ resistor is connected to an AC voltage source with an rms voltage of 120 V. (a) What is the maximum voltage across the resistor? (b) What is the maximum current through the resistor? (c) What is the rms current through the resistor? d) What is the average power dissipated by the resistor?
Solution:
The rms value of current and voltage shows the alternating quantity of the voltage and current.
Given that V(rms) = 120 V, R = 1.5 kΩ
a) The maximum voltage across the resistor is given as:
b) The maximum current through the resistor is:
c) The rms current through the resistor is:
d) The average power dissipated by the resistor is:
Answer:
The final velocity is 8 m/s and its direction is along the positive x-axis
Explanation:
Given :
Mass, m₁ = 2000 g = 2 kg
Mass, m₂ = 4000 g = 4 kg
Initial velocity of mass m₁, v₁ = 24i m/s
Initial velocity of mass m₂, v₂ = 0
According to the problem, after collision the two masses are stick together and moving with same velocity, that is, .
Applying conservation of momentum,
Momentum before collision = Momentum after collision
Substitute the suitable values in the above equation.
Answer:
Explanation:
Recall the formula for linear momentum (p):
which in our case equals 26.4 kg m/s
and notice that the kinetic energy can be written in terms of the linear momentum (p) as shown below:
Then, we can solve for the mass (m) given the information we have on the kinetic energy and momentum of the particle:
Now by knowing the particle's mass, we use the momentum formula to find its speed:
Answer:
2.05 radians/s
Explanation:
This is a simple harmonic motion. The angular frequency of a loaded spring is given by
where is the spring constant and
is the mass on the spring.
Using the known values,