Answer:
a = (V2 - V1) / t for uniform acceleration
t = (20 - 15/ m/s / 2 m/s^2 = 2.5 s
S = V1 t + 1/2 a t^2 distance covered
S = 15 * 2.5 + 2 / 2 * 2.5^2 = 37.5 + 2.5*2
S = 37.5 + 6.25 = 43.75 m
T = tension force in the rope in upward direction
m = mass of the box attached at end of rope = 56 kg
W = weight of the box in downward direction due to gravity
a = acceleration of the box in upward direction = 5.10 m/s²
weight of the box is given as
W = mg
inserting the values
W = (56) (9.8)
W = 548.8 N
force equation for the motion of the box is given as
T - W = ma
inserting the values
T - 548.8 = (56) (5.10)
T = 834.4 N
Answer:
specific heat of the substance
answer: 340 m/s
explanation: in this instance, the sound wave travels 340 meters in 1 second, so the speed of the wave is 340 m/s. remember, when there is a reflection, the wave doubles its distance. in other words, the distance traveled by the sound wave in 1 second is equivalent to the 170 meters down to the canyon wall plus the 170 meters back from the canyon wall.
