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Oksi-84 [34.3K]
3 years ago
11

25/100 simplified ? and if there’s any work pls show it

Mathematics
2 answers:
cluponka [151]3 years ago
8 0

Answer:

1/4

Step-by-step explanation:

Find HCD (Highest Common Factor) for both numerator and denominator.

The HCF for 25 and 100 is 25

Now divide the numerator and denominator by 25  

(25/25) / (100/25)

1/4

And Viola, you got your simplified form!

svetlana [45]3 years ago
4 0

Answer:

\frac{1}{4}

Step-by-step explanation:

25/100

divide both sides with 25

\frac{25 \div 25 }{100 \div 25}

simplify

= 1/4

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<h3>Answer: Choice B)  0</h3>

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Explanation:

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<h3>Answer: Choice B</h3><h3>-2x^2+250x-2000</h3>

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Explanation:

x = number of scooters made and sold

Each scooter costs $150 to make. If you made x of them, then it costs 150x dollars. Then tack on the fixed cost of $2000 to get the expression 150x+2000

The cost function is C(x) = 150x+2000. We'll subtract this from the revenue function R(x) to get the profit P(x)

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Question 4

<h3>Answer: Choice B</h3>

\left\{x\in \mathbb{R} \big| \ x \ne -2, x \ne 1\right\}

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Explanation:

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I started with the outer function g(x) and replaced each x with f(x) in the second step. Then I plugged in f(x) = x^2+x-3 and simplified. Factoring the denominator is helpful to determine where the denominator becomes zero. Specifically, it happens when x = -2 and x = 1. These x values must be kicked out of the domain to avoid a division by zero error.

So we start off with the real number line, and poke holes at x = -2 and x = 1.

The notation x \in \mathbb{R} means x is a real number. Then we tack on x \ne -2, x \ne 1

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(g \circ f)(x) = \frac{1}{(x+2)(x-1)}\\\\(g \circ f)(-1) = \frac{1}{(-1+2)(-1-1)}\\\\(g \circ f)(-1) = \frac{1}{(1)(-2)}\\\\(g \circ f)(-1) = \frac{1}{-2}\\\\(g \circ f)(-1) = -0.5\\\\

We don't get a division by zero error, so x = -1 is allowed. The same can be said about any other x value as long as it's not -2 and not 1 either.

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