Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer:
16. 200+3
17. 30+4+0.1+0.02+0.007
18. 200+70+6+0.1+0.03
19. 30000000+4000000+100000+20000+3000+6
Step-by-step explanation:
Answer:
Step-by-step explanation:
The answer is 281.25 ur welcome. ;)
Percent of students brought their lunch from home is 100-24= 76%
So, total students are in the six grade is
190 x 100/76 = 250 students
