All categories

3 years ago

QUICK!!

Mathematics

1 answer:

pochemuha3 years ago

8 0

Step-by-step explanation:

I don't know what the specific options are to be selected, but I can tell you what the situation is, and you can then pick the fitting options on your screen :

it is not a function, because 5 in set A (the domain) leads to 2 associated (functional result) values in B (the range).

but in order to be a function, every input value must have exactly one resulting output value. which is violated here.

You might be interested in

(a^3)^6 = (a^2)^x what is x?

alexgriva [62]

Answer:

Step-by-step explanation:

Solution

Here,

(a^3)^6=(a^2)^x

or, a^18=a^2x

or, 18=2x

or, x=18/2

x=9

8 0

3 years ago

ONLY ANSWER NUMBER 1!<br> name the supplement of

Illusion [34]

Answer:

It's angle ABE

Step-by-step explanation:

It's supplementary because the sum of the measurements of both angles EBC and ABE is 180°

3 0

3 years ago

Will mark a Brainiest

Xelga [282]

Answer:

37.5%

Step-by-step explanation:

you have 8 slices that should represent 100% so 100 divide 8 is 12.5

12.5 multiply by the three red sections you have then you get 37.5%

6 0

3 years ago

Pls help meeeeeeeee will give BRAINLIEST

inn [45]

Answer:

It's d) 4r+13b+16

Step-by-step explanation:

Hope this helps!

8 0

3 years ago

Read 2 more answers

If p and q are both true, then which of the following statements has the same truth-value as ~p → q?

olganol [36]

If p and q are both true, then

$\neg p \implies q$

is an implication of the form

$F \implies T$

which is true, because every implication starting with false is true, i.e.

$F \implies T = T,\quad F \implies F = T$

So, we're looking for an expression evaluating to true. Let's see what we have:

A) is an AND proposition. Logical AND is true only if both parts are true. So, you have

$\neg P \land \neg Q = F \land F = F$

So it's not the right option.

B) is an OR proposition. Logical OR is true whenever one of the two parts is true. So, you have

$\neg P \lor\neg Q = F \lor F = F$

So it's not the right option.

C) is again an AND proposition. You have

$P \land \neg Q = T \land F = F$

So this is not the right option.

D) Finally, the last one is again an implication, and again it starts with false:

$\neg Q \implies P = F \implies T = T$

So this is true, and thus is the correct option.

8 0

3 years ago