All categories

3 years ago

4. Which unit of measurement is best for describing the yearly movement of Earth's seafloor?

Mathematics

2 answers:

GarryVolchara [31]3 years ago

7 0

Answer:

Millimeters

Step-by-step explanation:

Hope this helps!!

Damm [24]3 years ago

4 0

Answer:

In S.I units

Length= meters, but for distance travelled by Car Kilometer is preferred.

Mass= Kilogram,

For liquid=Liters.

In British system

Length is measured in Foots, and liquids in Pound.

Step-by-step explanation:

You might be interested in

PLEASE HELP ASAP!!!<br><br> Y= [?] degrees

Elis [28]

Answer:

y = 25 degrees

Step-by-step explanation:

We start with 115° and x -

115° + x = 180°

x = 180° - 115°

x = 65°

The sum of all of the angles of a triangle will <em>always</em> be 180 degrees -

x + y + 90° = 180°

We substitute x with 65° -

65° + y + 90° = 180°

y = 180° - 65° - 90°

y = 90° - 65°

y = 25°

6 0

3 years ago

I need help on this it’s about trig identities

Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

$\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha$

$\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha }{cos\alpha (1 + sin\alpha) }$

$\frac{1 + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha }{cos\alpha + sin\alphacos\alpha }$

$\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha }$

$\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }$

$\frac{2}{cos\alpha }$

2sec $\alpha$

2.-

sec²x - tanxsecx

$\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}$

$\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}$

$\frac{1 - sinx}{cos^{2}x }$

$\frac{1 - sinx}{1 - sin^{2}x }$

$\frac{1 - sinx}{(1 - sinx)(1 + sinx)}$

$\frac{1}{1 + sinx}$

3 0

3 years ago

1 27 points from 35 points.

pishuonlain [190]

Answer:

127 from 35

127 - 35

Step-by-step explanation:

6 0

3 years ago

Fifty hundredths Seventy-five hundredths Twenty hundredths Eighty hundredths

MAXImum [283]

I think the answer is c sorry if I’m wrong

7 0

3 years ago

Prove that if one solution for a quadratic equation of the form x 2 + bx + c = 0 is rational (where b and c are rational), then

erica [24]

$x^2+bx+c = (x-r)(x-s)\\
x^2+bx+c = x^2-(r+s)x+rs\\\\
b = -(r+s)\\ c = rs$

Say r is rational. Suppose for a second, that s is not. Then, r+s is irrational. But this contradicts the fact that b is rational.

So, if one root is rational, then the other root is also rational

7 0

3 years ago