Answer:
For the given functions f(x) and g(x)
Step-by-step explanation:
Here, the given function are:
Now, simplifying for (f-g)(x) = f(x) - g(x):
Doing operation on LIKE TERMS, we get
f(x) - g(x) =
Hence, for the given functions f(x) and g(x)
What is the sum of the roots of the equation 2 x^2 + 5 x − 3 = 0?
1 answer:
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Answer:
The vertices are (-16,-5) and (14,-5)
The foci are (-26,-5) and (24,-5)
Please, see the attached file.
Thanks.
Answer:
V=15.44
Step-by-step explanation:
We have a formula
V=\int^{π/3}_{-π/3} A(x) dx ,
where A(x) calculate as cross sectional.
We have:
Inner radius: 5 + sec(x) - 5= sec(x)
Outer radius: 7 - 5=2, we get
A(x)=π 2²- π· sec²(x)
A(x)=π(4-sec²(x))
Therefore, we calculate the volume V, and we get
V=\int^{π/3}_{-π/3} A(x) dx
V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx
V=[ π(4x-tan(x)]^{π/3}_{-π/3}
V=π·(8π/3-2√3)
V=15.44
We use a site geogebra.org to plot the graph.
