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Kay [80]
3 years ago
8

PLEASE HELP NOOWWW I WILL GIVE BRAINLIEST

Chemistry
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

c

Explanation:

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1. Choose the alkyl halide(s) from the following list of C6H13Br isomers that meet each criterion below. 1) 1-bromohexane 2) 3-b
Vika [28.1K]

Answer:

See explanation

Explanation:

the compound that gives the fastest SN2 reaction with sodium methoxide- 1-bromohexane

the compound that gives the fastest SN1 reaction- 3-bromo-3-methylpentane

the compound(s) that undergo an SN1 reaction to give rearranged products- 1-bromo-2,2-dimethylbutane

the compound that is least reactive to sodium methoxide in methanol -

3-bromo-3-methylpentane

the compound(s) that can exist as diastereomers - 3-bromo-3-methylpentane

the compound(s) that can exist as enantiomers- 3-bromo-2-methylpentane

6 0
3 years ago
What is the charge of GaF3​
slavikrds [6]

Answer:

This charge transfer led to the formation of pentacoordinated square pyramidal MX·(YZ3) adducts with M·Y dative bond. Binding energies were -44.7 and -75.2 kcal/mol for interaction of GaF3 as the strongest acid with PtNCN

4 0
3 years ago
List two products derived from ethylene
laiz [17]
Ethylene is the starting material for the preparation of a number of two-carbon compounds including ethanol (industrial alcohol), ethylene oxide (converted to ethylene glycol for antifreeze and polyester fibres and films), acetaldehyde (converted to acetic acid), and vinyl chloride (converted to polyvinyl chloride).
8 0
2 years ago
Please help me with this homework
aleksandr82 [10.1K]
Answer is gas for sure and I think it’s ice for question 2
5 0
3 years ago
What is Keq for the reaction N2 + 3H2 2NH3 if the equilibrium concentrations are [NH3] = 3 M, [N2] = 1 M, and [H2] = 2 M?
Licemer1 [7]

Answer : The correct option is, (D) k_{eq}=1.125

Explanation : Given,

Concentration of NH_3 = 3 M

Concentration of N_2 = 1 M

Concentration of H_2 = 2 M

The given balanced equilibrium reaction is,

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for equilibrium constant for this reaction will be,

K_{eq}=\frac{[NH_3]^2}{[N_2][H_2]^3}

Now put all the given values in this expression, we get the value of K_{eq}

K_{eq}=\frac{(3)^2}{(1)\times (2)^3}

K_{eq}=1.125

Therefore, the value of K_{eq} for the given reaction is, 1.125

5 0
3 years ago
Read 2 more answers
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