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yan [13]
3 years ago
5

Write the orbital notation for element 53.

Chemistry
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

Its complete electron configuration is 1s22s22p63s23p64s23d104p65s24d105p5.

Explanation:

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14. All the following are necessary parts of a neutralization reaction except A. an indicator. B. a salt. C. water. D. an acid.
ValentinkaMS [17]

The correct answer is <em>B. a Salt </em><em>because The reaction of an acid and a base is called a neutralization reaction because the properties of both the acid and base are diminished or neutralized when they react. A neutralization reaction is a reaction of an acid with a base in aqueous solution to produce water and a salt, as shown by the following equation:</em>

<em>acid + base → salt + water</em>

<em />

<em>* Hopefully this helps:) Mark me the brainliest:) </em>

<em>∞ 234483279c20∞</em>

6 0
3 years ago
Acidis are,which means that they "eat away"at other materials
alexandr1967 [171]
Acids are corrosive, which means they 'eat away' at other materials.
5 0
3 years ago
What is the temperature of 1.485 moles of N₂ gas at a pressure of 1.072 atm and a volume of 20 L?
morpeh [17]

Answer:

178.67K

Explanation:

PV=nRT

T=PV/nR

= 1.072atm*20L/1.485mol*0.0821LatmK^-1

=178.67K

8 0
4 years ago
Consider the reaction of Mg3N2 with H2O to form Mg(OH)2 and NH3. If 4.33 g H2O is reacted with excess Mg3N2 and 6.26 g of Mg(OH)
Len [333]

Answer:

89.34%

Explanation:

First, write a balanced reaction.

Mg3N2 + <u>6</u>H2O --> <u>3</u>Mg (OH)2 + <u>2</u>NH3

Next determine the moles of the known substance, or limiting reagent ( H2O)

n= m/MM

n ( H2O) = 4.33/(1.008×2)+16

n(H2O)= 0.2403

Use the mole ratio to find the moles of Mg(OH)2

0.2403 ÷2

n (Mg (OH)2) = 0.1202

Next, find the theoretical mass of Mg (OH)2 that should have been produced

m= n × MM

m= 0.1202 × (24.305 + (16×2) +(1.008 ×2))

=7.007g

To find percentage yield, divide the experimental amount by the theoretical amount and multiply by 100.

6.26/ 7.007 × 100

=89.34%

7 0
3 years ago
How many bacteria can fit into an animal cell
melisa1 [442]
The size of most eukaryotic animal cells range from 1 - 30 micrometers while the size of, let's say coccus bacteria is between 0.5 - 1.0 micrometers. So, if the largest animal cell is filled with the largest coccus bacteria, we can say that 30 bacteria can fit inside.
5 0
3 years ago
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