12x² - 3.5y + 10y + 1.5x² + y Combine like terms
13.5x² + 7.5y
A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
Answer: x = 1
Step-by-step explanation:
substitute 1 for x
1/2(10(1)+6) = -2(1)+10
1/2(10+6) = -2+10
5+3 = -2+10
8=8
Answer:
906
Step-by-step explanation:
Answer:
1. y = 4
2. x = 10
3. n = 6
4. m = 4
5. h = 2
Step-by-step explanation:
Hope this helps!!
