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butalik [34]
2 years ago
9

Perimeter ILL MARK BRAINLY

Mathematics
2 answers:
Kipish [7]2 years ago
8 0

Answer:

The perimeter is 24 in2

Step-by-step explanation:

You have to add up all of the sides together

daser333 [38]2 years ago
3 0

Answer:

the answer 24

Step-by-step explanation:

<u>P</u><u>=</u><u> </u><u>1</u><u>0</u><u>+</u><u>6</u><u>+</u><u>8</u><u>=</u><u>2</u><u>4</u><u> </u><u>in</u>

<u>because</u><u> </u><u>perimeter</u><u> </u><u>is</u><u> </u><u>just</u><u> </u><u>adding</u><u> </u>

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20/48

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
1 year ago
PLEASE HELP URGENT! AND IM DUMB! WORTH 6 POINTS!
uysha [10]

Answer:

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6 0
3 years ago
Which set of values could be the side lengths of a 30-60-90 triangle?
jeyben [28]
If we say that side "a" is the shortest (adjacent), side "b" is the second shortest (opposite), and side "c" is the longest (hypotenuse): then angle A would be 30°,  angle B would be 60°, and angle C would be 90°

tan B = b/a
 or
a tan B = b

they have 4 as the smallest value in all four options, so we know that a=4

4 tan 60° = b
tan 60° = √3
so, 4 tan 60° = 4√3
b=4√3

that leaves two options left, so now we find "c":

c^2 = (a^2) + (b^2)
OR
c= \sqrt{a^{2} + b^{2}}

c= \sqrt{4^{2}+(4\sqrt{3})^{2}}

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so a=4, b=4√3, and c=8

Making your answer B
3 0
2 years ago
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