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Yakvenalex [24]
2 years ago
10

Tam giác ABCD có góc B = 65 Độ góc C = 115 Độ hỏi góc A bằng bao nhiêu độ

Mathematics
2 answers:
Black_prince [1.1K]2 years ago
7 0

Answer:

a

Step-by-step explanation:

kasi yun ang tama at

nain tindi han ko

defon2 years ago
4 0
A





pls give me brainliest!! <3 have a good day
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Change 725 percent to a mixed number
kvv77 [185]
The answer to your question is 7 25/100 or simplified to 7 1/4 because percent means out of 100 and if there is 700 then there is 7 wholes thn you have 25/100 or 1/4
7 0
3 years ago
Given the following geometric sequence, find the common ratio: {16, 64, 256, ...}.
Anettt [7]

Answer:

The common ratio is 4

Step-by-step explanation:

We need to divide a term by the previous term to find the common ratio in a geometric sequence:

64 ÷ 16 = 4

256 ÷ 64 = 4

By doing it twice we can confirm that the common ratio is 4

8 0
3 years ago
Read 2 more answers
The sum of a number (n) and 14 is 72. Which equation shows this relationship
NemiM [27]
I believe the answer is N+14=72
6 0
3 years ago
Read 2 more answers
Help pleaseeeeeee, I need help
Arlecino [84]

Answer:

15, 60, and 61

Step-by-step explanation:

First we have to find the 3rd side length from 2 side length chosen. So let’s pick 8 meters and 11 meters, to find the third side length we use the Pythagorean theorem: c^2 = a^2 + b^2

c = 11^2 + 8^2 = 121 + 64 = 185 = 13.6

13.6 isn’t one of the answers so we can’t pick 11 & 8. Let’s try 11 & 15:

c = 15^2 + 11^2 = 225 + 121 = 346 = 18.6

18.6 isn’t one of the answers either. Let’s try 15 & 60:

c = 60^2 + 15^2 = 3600 + 225 = 3825 = 61.85

61.85 might be it but let’s try one more just in case:

c = 60^2 + 61^2 = 3600 + 3721 = 7321 = 85.6

Nope! That means 15, 60, and 61 are the answer. I hope this is correct!

5 0
3 years ago
Help pleaseeeeeeeeeeeeeeeeeeeeeee
bixtya [17]

Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

3 0
3 years ago
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